Context
On words a^x b^y, the series has three open cones with gradients (-3,0), (-1,-1), and (0,-3).
Proof or evidence
A two-ambiguous automaton would yield at most two affine forms on each eventual product cell, but two affine zero sets cannot cover a full-dimensional lattice subset in all three cones. Three one-state components give the matching upper bound.
Verification notes
The review checked all 131,071 binary words through length 16, excluded 31,878 pairs of small affine forms on an 11-by-11 hostile grid, and rechecked every residue-cell/cone rank. The proof remains the cut-state and affine-cover argument, not finite testing.
Limitations
- The result establishes one exact intrinsic ambiguity value; it is not a classification theorem.
- No novelty or external-review claim is made.
Notes
The proof restricts to a*b*, factors at the block boundary, and uses three persistent gradients. The earlier path-scheme proof is withdrawn. The primary unary source is identified but not held in repository custody. Novelty is not assessed. The separate all-k baseline-robustness theorem is not promoted because its full proof packet is absent from the public repository.