Context
T153 invited a direct strategy: make a language's finite-horizon response table larger than every fixed scaffold bound. T154 proves that the raw cardinality version of this strategy cannot work, because the continuation universe itself grows more slowly than one fixed abstract-view envelope.
Hypotheses and scope
- The input alphabet is finite and nonempty.
- The response coordinate for each selected continuation is Boolean.
- The comparison uses the generic abstract-view bound V_r from T153, not a tighter reachable-view bound for a particular automaton.
Proof or evidence
There are at most 2^N response rows for N continuations. With d=max(2,s), k=2, one working label, and one control state, T153 has R=h+1 and V_R at least 2^(d^(h+1)), while the number of words of length at most h is at most d^(h+1). The checker verifies the exact recurrence on 40 cases and the exponent inequality on 16,448 cases.
Verification notes
The proof was checked separately at horizon zero and for unary and nonunary alphabets. Mutants that reduce degree below the alphabet size or hold the readable radius at one fail in 8,510 and 16,383 audited cases respectively.
Limitations
- The theorem is a no-go result for raw row cardinality, not a language-recognition theorem or a scaffold construction.
- Abstract view counts can include unreachable views, so exceeding a tighter automaton-specific bound may still be useful.
- Structured invariants involving cut advance, horizon coherence, algebra, allocation, or transport remain open.
- The counting ingredients are elementary and no literature-priority or external-review claim is made.