Context
The census tests how frequently the quotient failure occurs and identifies a narrow family of ordinary-quotient controls.
Hypotheses and scope
- The alphabet is , both words are nonempty, and .
Proof or evidence
The checker enumerates all words in the domain, constructs both automata, and exhausts compatible partitions for ordinary and left quotients.
Verification notes
The totals split as 9, 54, and 243 cases at total word lengths 2, 3, and 4; the corresponding no-quotient counts are 6, 48, and 234.
Limitations
- A finite census is evidence, not a general theorem; the general proof is recorded separately as FPRD-SH-T05.